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Is n odd?
(1) n is divisible by 3
(2) 2n is divisible by twice as many positive integers as n
Solution:
(1) 不足, n = 3k, k could be even or odd, then n could be even or odd
(2) 牽扯到因數個數的問題
假設 n = (X^a)(Y^b)(Z^c).........
n 的因數個數為 (a+1)(b+1)(c+1)..........
現在探討 2n 所以我們假設 n = (2^a)(Y^b)(Z^c).........
n 的因數個數為 (a+1)(b+1)(c+1)..........
2n = (2^(a+1))(Y^b)(Z^c).........
2n 的因數個數為 (a+2)(b+1)(c+1)..........
由於兩者因數個數差了兩倍
2(a+1)(b+1)(c+1)..........
=(a+2)(b+1)(c+1)..........
顯然的 a = 0, 也就是 n 沒有 2 這個因數
n is odd
Answer (B)
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